Question 885291
A marine biologist wants to set up n aquarium containing 3% salt water. He has two tank on hand that contain 6% and 2% salt water. How much water from each tank must he use to fill a 32-gallon aquarium with a 3% saltwater mixture?
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Let x = amount (gallons) of 6% salt water
then
32-x = amount (gallons) of 2% salt water
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our equation:
.06x + .02(32-x) = .03(32)
.06x + 0.64 -.02x = 0.96
.04x + 0.64 = 0.96
.04x = 0.32
x = 8 gallons of 6% salt water
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amount of 2% salt water:
32-x = 32-8 = 24 gallons