Question 884822
Convert the equation to the standard form for a hyperbola by completing the square on x and y. 
y2 - 25x2 + 4y + 50x - 46 = 0
{{{-25x^2+50x+y^2+4y=46}}} 
{{{- 25(x^2-2x+1)+(y^2+4y+4)=46-25}}}
{{{-25(x-1)^2+(y+2)^2=21}}}
{{{(y+2)^2-25(x-1)^2=21}}}
{{{(y+2)^2/(21)-25(x-1)^2/(25/21)=1}}}
This is an equation of a hyperbola with vertical transverse axis and center at (1,-2)
Its standard form of equation: {{{(y-k)^2/a^2-(x-h)^2/b^2=1}}}