Question 885207
{{{y=x^2-x+1}}}<-->{{{y-1=x^2-x}}}<-->{{{y-1+1/4=x^2-x+1/4}}}<-->{{{y-3/4=(x-1/2)^2}}}<-->{{{y=(x-1/2)^2+3/4}}}
so the graph is a parabola, with axis {{{x=1/2}}} and a minimum at {{{x=1/2}}} with
{{{y=3/4}}} .
{{{graph(300,300,-5,5,-1,9,x^2-x+1)}}}