Question 885103
In one hour, the objects are 201 miles apart (402/2)
A + B = 201
A = B+3
Substitute the known value of A from the second equation into the first.
A + B = 201
(B+3) + B = 201
2B + 3 = 201
Subtract 3 from each side
2B = 198
Divide each side by 2
B = 99
.
The slower object is traveling 99 mph; the faster, 102 mph
Add them together and they are traveling 201 mph
201 mph * 2 hours = 402 miles