Question 885074
how do you find the solutions for theta in this problem: 
for interval: (0,2π)
3 tan^2(theta) - 1 = sec^2(theta)
{{{3tan^2(theta)-1=sec^2(theta)}}}
{{{(3sin^2(theta))/(cos^2(theta))-1=1/cos^2(theta)}}}
lcd: {{{cos^2(theta)}}}
{{{3sin^2(theta)-cos^2(theta)=1}}}
{{{3sin^2(theta)-(1-sin^2(theta))=1}}}
{{{3sin^2(theta)-1+sin^2(theta)=1}}}
{{{4sin^2(theta)=2}}}
{{{sin^2(theta)=(1/2)}}}
{{{sin(theta)}}}=±√(1/2)=±√2/2
{{{theta}}}= π/4, 3π/4, 5π/4, 7π/4