Question 74520
Let x= the measure of angle B

Then (2x-40)=the measure of angle C
{x+(2x-40)}=the sum of the measures of angles B and C
So {x+(2x-40)}-100=the measure of angle A

Then our equation to solve is

A+B+C=180  or

x+(2x-40)+{x+(2x-40)}-100=180  get rid of parens and brackets

x+2x-40+x+2x-40-100=180  collect like terms
6x-180=180  add 180 to both sides

6x=360  divide both sides by 6
x=60 degrees---------------------------the measure of angle B

2x-40=120-40=80 degrees---------------------the measure of angle C

x+2x-40-100=180-140=40 degrees ---------------the measure of angle A

CK
60+80+40=180
180=180
measure of C is 40 degrees less than the twice the measure of angle B.
2*60-40=80
80=80
angle A measures 100 degress less than the sum of the measures of angle B and angle C
60+80-100=40
40=40




Hoe this helps----ptaylor