Question 885054
Let {{{ k }}} = the constant of variation
{{{ 40^2 = k*55 }}}
{{{ 1600 = k*55 }}}
{{{ k = 29.091 }}}
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Let {{{ s }}} = the stopping distance in feet
{{{ 65^2 = k*s }}}
{{{ 4225 = k*s }}}
{{{ s = 4225/29.091 }}}
{{{ s = 145.234 }}}
{{{ .234*12 = 2.8 }}}
About 145 ft 3 in