Question 885029
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Let *[tex \Large w] represent the width.  Then the length must be *[tex \Large 3w\ -\ 1].  The area of a rectangle is the length times the width.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (3w\ -\ 1)w\ =\ 44]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3w^2\ -\ w\ -\ 44\ =\ 0]


Solve for *[tex \Large w]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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