Question 884978
Let {{{N-2}}},{{{N}}}, and {{{N+2}}} be the three consecutive integers.
{{{(N-2)^2+N^2+(N+2)^2=331}}}
{{{N^2-4N+4+N^2+N^2+4N+4=331}}}
{{{3N^2+8=331}}}
{{{3N^2=333}}}
{{{N^2=111}}}
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Something is wrong with your problem setup because {{{111}}} is not a perfect square so {{{N}}} is not an integer.
The closest sum of squares of 3 consecutive odd integers is 371.
Please repost.