Question 884975
Perpendicular lines have slopes that are negative reciprocals.
{{{y=3x+4}}}
{{{m=3}}}
.
.
{{{m[p]*3=-1}}}
{{{m[p]=-1/3}}}
Use the point slope form of a line,
{{{y-(-2))=-(1/3)(x-1)}}}
{{{y+2=-(1/3)x+1/3}}}
{{{y=-(1/3)x+1/3-6/3}}}
{{{y=-(1/3)x-5/3}}}
.
.
.
{{{a=-1/3}}}
{{{b=-5/3}}}