Question 884813


16x^2-25

16x^2+0x-25

here a= 16 b=0 and c =-25

Find the roots of the equation by quadratic formula							
							
a=	16    	b=	0    	c=	-25    		
							
b^2-4ac=	0    	-	-1600    				
b^2-4ac=	1600    			{{{sqrt(	1600    	)}}}=	40    
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(	-0    	+	40    	)/	32    		
x1=	5/4						
x2=(	-0    	-40    	) /	32    			
x2=	-5/4						

(5/4, -5/4)