Question 884126
A + B + C = 29
B = 2A-4
C = {{{2/3}}}A
Substitute the known values of B & C into the first equation.
A + B + C = 29
A + (2A-4) + {{{2/3}}}A = 29
Add
3{{{2/3}}}A - 4 = 29
Add 4 to each side
3{{{2/3}}}A = 33
{{{11/3}}}A = 33
Let's get rid of that pesky fraction; multiply each side by 3
11A = 99
Divide each side by 11
A = 9
.
Now that we have A, we can find the other lengths.
B is (2*9) - 4, or 18-4, or 14
C is {{{2/3}}}of 9, or 6
Add them all together to prove -- 9 + 14 + 6 = 29
Success!