<PRE><B>Question 884761</B>
The Vertex and Foci of curve y^2-8x-6y-23=0 is at ?
8x+23 = y^2-6y
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Complete the square:
y^2-6y+9 = 8x+32
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Factor:
(y-3)^2 = 8(x+4)
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Vertex at (-4,3)
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4p = 8
p = 2
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The graph is a parabola opening to the right from (-4,3)
Foci: (-4+2,3) = (-2,3)
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Cheers,
Stan H.
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