Question 884605
let sides are a, b, c

a=3b-6
c=a+8
a+b+c=80

3b-6+b+a+8=80
3b-6+b+3b-6+8=80
7b-4=80
7b=84
b=12
a=3b-6=3(12)-6=30
c=a+8=30+8=38