Question 74459
Let the numbers be x and y
Then x + y = 52
Let x be the larger of the two numbers.
When the larger is divided by the smaller, the quotient is 9 and the remainder is 2.
==>  x = 9y + 2
PLugging in this value of x in the first equation we have,
9y + 2 + y = 52
==> 10y + 2 = 52
==>  10y = 52 - 2 [subtracting 2 from both the sides]
==>   10y = 50
==>   y = 50/10
==>  y = 5
So x = 9y + 2
     = 9*5 + 2
    = 45 + 2
    = 47
So the numbers are 47 and 5.



Good Luck!!!