Question 884665
a man 38 years old has a son 14 years old. how many years ago was the father seven times as old as his son?
let x=years ago father was seven times as old as his son
{{{(38-x)/(14-x)=7}}}
38-x=98-7x
6x=60
x=10
how many years ago father was seven times as old as his son? 10