Question 884628
<u>A man is 41 years old and his son is 9</u>
Let x be 'the number of years ahead' when the father will be three times as old as the son
41 + x = 3(9+x)
  14 = 2x
   7 = x
In seven years, the father will be three times as old as the son
{{{48 = 3*16}}}