Question 884602
<pre>
By formula:

P(none are rejected) + P(1 is rejected) + P(2 are rejected) =

{{{expr(12!/(0!(12-0)!))(.4)^0(1-.4)^(12-0)}}}{{{""+""}}}{{{expr(12!/(1!(12-1)!))(.4)^1(1-.4)^(12-1)}}}{{{""+""}}}{{{expr(12!/(2!(12-2)!))(.4)^2(1-.4)^(12-2)}}}

Or by calculator:

binomcdf(.12,.4,2)

.0834433229

Edwin</pre>