Question 74439
{{{(2a)^2=24}}}
{{{sqrt((2a)^2)=sqrt(24)}}}
{{{cross(2/2)a=(0+-sqrt(24))/2}}}Divide both sides by 2  
{{{a=(0+-sqrt(24))/2}}}
{{{a=(0+-sqrt(6)sqrt(4))/2}}}Rewrite the square root with one perfect square as factor
{{{a=(0+-sqrt(6)(2))/2}}}
{{{a=(0+-sqrt(6)*cross(2))/cross(2)}}}Cancel common terms
{{{a=0+-sqrt(6)}}}There's the simplified answer note: ignore the zero. it is only used to make the plus/minus.
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Check:
{{{(2(sqrt(6)))^2=24}}}Plug in {{{sqrt(6)}}}
{{{4*6=24}}}
{{{24=24}}}works
{{{(2(-sqrt(6)))^2=24}}}Plug in {{{-sqrt(6)}}}
{{{4*6=24}}}
{{{24=24}}}works