Question 884457
The length of a rectangle is 6 ft. longer than twice the width. If the perimeter is 90 ft. find the length and width of the rectangle.
<pre>
Let width be W, and length, L
Then L = 2W + 6 ------- eq (i)
Since perimeter = 2L + 2W, then 2L + 2W = 90
2(L + W) = 2(45) ------ Factoring out GCF, 2
L + W = 45 ------------ eq (ii)
2W + 6 + W = 45 ------- Substituting  2W + 6 for L in eq (ii)
3W = 39
W, or width = {{{39/3}}}, or {{{highlight_green(highlight_green(13))}}} ft
Use this info to determine the value of L, or the length.
Then do a check!! 

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