Question 884457
A dimension of a rectangle is x ft. longer than k the other dimension, y. If the perimeter is p ft. find the dimensions x and y of the rectangle.


x=k+y and 2x+2y=p.
The unknown variables are x and y.
Solve for x and y.


{{{2x+2y=p}}}
{{{2(k+y)+2y=p}}}
{{{2k+2y+2y=p}}}
{{{4y+2k=p}}}
{{{4y=p-2k}}}
{{{highlight(y=(p-2k)/4)}}}
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Return again to the equation from the description for how x and y are related.
{{{x=k+y}}}
{{{x=k+(p-2k)/4}}}
{{{x=4k/4+(p-2k)/4}}}
{{{x=(4k+p-2k)/4}}}
{{{highlight(x=(2k+p)/4)}}}
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If you use your given values from the beginning, there could be fewer steps needed.  If you chose to solve the problem all symbolically, then you would finish by substituting the given values from the problem description into the solved formulas to compute the x and y values.