Question 884387
{{{y=x^2-16^x}}}
{{{graph(300,300,-5,5,-5,5,x^2-16^x)}}}
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I used Newton's method with
{{{y=x^2-16^x}}}
{{{dy/dx=2x-log((16))*16^x}}}
and a starting value of {{{x=-1}}}
and within 6 iterations it converged to 
{{{x=-1/2}}}