Question 884364
1.{{{15x-20y=-1}}}
2.{{{15y=2+5x}}}
From eq. 2,
{{{5x=15y-2}}}
{{{15x=45y-6}}}
Substitute into eq. 1,
{{{45y-6-20y=-1}}}
{{{25y=5}}}
{{{y=5/25}}}
{{{highlight(y=1/5)}}}
Then,
{{{5x=15(1/5)-2}}}
{{{5x=3-2}}}
{{{5x=1}}}
{{{highlight(x=1/5)}}}