Question 884287
Acceleration based on initial and final velocity and distance traveled.
{{{a=(v[f]^2-v[i]^2)/s}}}
Convert velocities to {{{m/s}}}
{{{108}}}{{{km/hr}}}*{{{1000/3600}}}{{{(m/km)(hr/sec)}}}={{{30}}}{{{m/s}}}
{{{36}}}{{{km/hr}}}*{{{1000/3600}}}{{{(m/km)(hr/sec)}}}={{{10}}}{{{m/s}}}
{{{a=(v[f]^2-v[i]^2)/s}}}
{{{a=(10^2-30^2)/200=(100-900)/200=-800/200=-4}}}{{{m/s^2}}}
.
.
.
Final velocity given initial velocity, acceleration, and time.
{{{v[f]=v[ii]+at}}}
{{{10=40-4t}}}
{{{-4t=-30}}}
{{{t=30/4=15/2}}}{{{sec}}}