Question 884283
{{{(3+i)/(5-2i)=((3+i)/(5-2i))*((5+2i)/(5+2i))}}}
{{{(3+i)/(5-2i)=(15+6i+5i+2i^2)/(25+10i-10i-4i^2)}}}
{{{(3+i)/(5-2i)=((15-2)+11i)/(25+4)}}}
{{{(3+i)/(5-2i)=(13+11i)/29}}}