Question 884229
Find the probability that neither of the cards is a heart.
There are 13 hearts in a deck of 52 leaving 39 non-hearts.
Also the two cards are picker without replacement.
{{{P(NH)=(39/52)(38/51)=19/34}}}
So then the probability of at least 1 Heart is,
{{{P(1H)+P(NH)=1}}}
{{{P(1H)=1-P(NH)}}}
{{{P(1H)=1-19/34}}}
{{{highlight(P(1H)=15/34)}}}