Question 884045
First odd integer : {{{N}}}
Next consecutive odd integer : {{{N+2}}}
{{{N(N+2)=5+N}}}
{{{N^2+2N=5+6N}}}
{{{N^2-4N-5=0}}}
{{{(N-5)(N+1)=0}}}
Two solutions:
{{{N-5=0}}}
{{{N=5}}}
and
{{{N+1=0}}}
{{{N=-1}}}