Question 884200
Let the number be x
So the three consecutive integers are
x, x+1 and x+2

{{{x + (x+1) + (x+2) = 4080}}}
{{{3x + 3 = 4080}}}
{{{3x = 4080 -3}}}
{{{3x = 4077}}}
{{{x = 4077/3}}}
{{{x = 1359}}}
So the numbers are 1359, 1360 and 1361

Use the same idea to solve for the product (the other problem you entered)