Question 884026
{{{y=a(x+9)(x+3)}}}
{{{y=a(x^2+12x+27)}}}
{{{y=a(x^2+12x)+27a}}}
{{{y=a(x^2+12x+36)+27a-36a}}}
{{{y=a(x+6)^2-9a}}}
So then,
{{{-9a=-1}}}
{{{a=1/9}}}
{{{y=(1/9)(x+9)(x+3)}}}