Question 884010
Complete the square and put the equation into vertex form.
{{{y=x^2+x-2}}}
{{{y=(x^2+x+1/4)-2-1/4}}}
{{{y=(x+1/2)^2-8/4-1/4}}}
{{{y=(x+1/2)^2-9/4}}}
a) Upwards, coefficient of {{{(x+1/2)^2}}} is {{{1}}}.
b) {{{x=-1/2}}}
c) Vertex: ({{{-1/2}}},{{{-9/4}}})
d) When {{{x=0}}},{{{y=(1/2)^2-9/4=-2}}}
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{{{drawing(300,300,-5,5,-5,5,grid(1),circle(0,-2,0.2),circle(-1/2,-9/4,0.2),blue(line(-1/2,10,-1/2,-20)),graph(300,300,-5,5,-5,5,x^2+x-2))}}}