Question 883602
I need help to answer this question, I have tried but I just don't remember how to do it. The problem goes something like,
The width of a certain rectangle is 3 meters more than half its length. If the perimeter of the rectangle is 204 meters, what is the length of the rectangle?
I really want to know how to solve this problem for any future problems that i may get like it. thank you
<pre> <font face = "Tohoma" size = 4 color = "indigo"> <b>
Let length of rectangle be L
Then width (W) of rectangle is: {{{(1/2)L + 3}}}, or {{{L/2 + 3}}}
2L + 2W = Perimeter of a rectangle
{{{2L + 2(L/2 + 3) = 204}}} ------ Substituting {{{L/2 + 3}}} for W    
2L + L + 6 = 204
3L = 204 - 6
3L = 198
L, or length = {{{198/3}}}, or {{{highlight_green(highlight_green(66))}}} m
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