Question 883553
In a collection of nickels and quarters, there are two more nickels than quarters.  How many of each coin are there if the collection is worth $3.40?

We are trying to assist our daughter with this problem and can't find the solution, please help.
<pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Let the number of quarters be Q
Then the number of nickels is: Q + 2
As each quarter is worth $0.25, and each nickel is worth $0.05, we can say that:
.25(Q) + .05(Q + 2) = 3.4
.25Q + .05Q + .1 = 3.4
.25Q + .05Q = 3.4 - .1
.3Q = 3.3
Q, or the number of quarters = {{{3.3/.3}}}, or {{{highlight_green(highlight_green(11))}}}
Number of nickels: 11 + 2, or {{{highlight_green(highlight_green(13))}}}
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Check
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Quarters: 11, for a quarter-amount of 11(.25), or $2.75
Nickels:   <u>13</u>, for a nickel-amount of 13(.05), or   <u>$0.65</u>
Total:      24  coins,     for a total amount of        $3.40
As seen also, there are 2 more nickels than quarters (13 nickels to 11 quarters)</font face = "Tohoma" size = 4 color = "indigo"></b>