Question 883388
{{{f(x)=x^2+5x+6=(x+2)(x+3)}}}
{{{g(x)=x^2+3x-40=(x+8)(x-5)}}}
{{{g(x)/f(x)=((x+8)(x-5))/((x+2)(x+3))}}}
When the denominator goes to zero, the function is undefined.
{{{x+2=0}}}
{{{x=-2}}}
and
{{{x+3=0}}}
{{{x=-3}}}
These two values are not in the domain.