Question 883405
{{{d=((Vo^2)/g)sin(2theta)}}}  2*theta
************ g = 32 ft/sec^2 *************
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a) Write an expression for the distance the ball travels in terms of {{{theta}}}
That is the distance in terms of theta.
Vo and g are constants.
Sub for them if you want.
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b) Find the distance Ms. King's ball travelled if the angle between the initial path of the ball and the ground measured 60°.
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{{{d=((Vo^2)/g)sin(2theta)}}}
{{{d=(100^2/32)sin(120)}}}
{{{d=(10000/32)(sqrt(3)/2)}}}
d =~ 135 feet