<PRE><B>Question 883345</B>
General term of sequence is {{{-35+(n-1)*2=-35+2n-2=-37+2n}}}.


The sum of some consecutive n terms is 37.
{{{(n/2)(-35+(2n-37))=37}}}, half of n time the sum of first and last terms;
{{{(n/2)(2n-72)=37}}}
{{{n(n-36)=37}}}
{{{n^2-36n=37}}}
{{{highlight_green(n^2-36n-37=0)}}}
Easily factored:
{{{(n-37)(n+1)=0}}}


The answer having meaning is n=37.


CHECK:
{{{(37/2)(-35+2*37-37)}}}
{{{(37/2)(74-35-37)}}}
{{{(37/2)(2)}}}
{{{37}}}.
This works.


37 terms of the sequence summed </PRE>