Question 883161
log2(x - 6) + log2(x - 4) = log2 x solve the logarithmic equation. and round.
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solve for x
{{{log(2,(x-6))+log(2,(x-4))=log(2,(x))}}}
{{{log(2,(x-6)(x-4))=log(2,(x)))}}}
x=(x-6)(x-4)
x=(x^2-10x+24)
x^2-11x+24=0
(x-3)(x-8)=0
x=3
or
x=8