Question 882939
 {{{x^2-2x-15<0}}}
first solve
 {{{x^2-2x-15=0}}}
{{{(x-5)*(x+2)=0}}}
x = 5 or x = -2
So for values of x between -2 and 5,
x^2-2x-15 is less than zero
(-2,5) is our solution