Question 882992
{{{(a^3+27b^3)/(a^2-9b^2)}}}
The numerator, you have to use the "special Factoring formula" as the "Sum of cubes"
namely: (a^3 + b^3) = (a+b)(a^2- ab + b^2), in your problem this would be
: 
{{{((a+3b)(a^2- 3ab + 9b^2))/((a-3b)(a+3b))}}}; factored the denominator as difference if squares
Cancel (a+3b)
{{{((a^2- 3ab + 9b^2))/((a-3b))}}}; about all you can do with it