Question 883011
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If you write the given function in vertex form, i.e. *[tex \Large p(x)\ =\ (x\ -\ h)^2\ +\ k)], you can determine the coordinates of the given function's vertex


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ (x\ +\ 2)^2\ +\ 0]


so the vertex of the given function is *[tex \Large (-2,\,0)]


If you move 6 units to the right, then you need to add 6 to the *[tex \Large x]-coordinate of the original vertex to find the *[tex \Large x]-coordinate of the translated function vertex.  Since you are only translating 6 units right, and there is no mention of any vertical translation, the *[tex \Large y]-coordinate of the vertex remains the same for the given translation.  Hence, the vertex of the translated function is *[tex \Large (4,\,0)].


Pick the answer that indicates this new vertex.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \