Question 74179
Because if you use the change of base formula
{{{log_[b](a)=log(a)/log(b)}}}If you let b=1, you get
{{{log_[1](a)=log(a)/log(1)}}}
Log(1)=0 since x^0=1 so it becomes
{{{log_[1](a)=log(a)/0}}}Which is not possible for any value of a.