Question 882948
Wherever there is an {{{x}}}, replace it with {{{2/3}}} then simplify,
{{{(1/2)x^2-5x+2=(1/2)(2/3)^2-5(2/3)+2}}}
{{{(1/2)x^2-5x+2=(1/2)(4/9)-10/3+2}}}
{{{(1/2)x^2-5x+2=2/9-30/9+18/9}}}
{{{(1/2)x^2-5x+2=((2-30+18))/9}}}
{{{(1/2)x^2-5x+2=highlight(-10/9)}}}