<PRE><B>Question 882734</B>
Find the value of secC^2-tanC^2 if sinC=12/13 and the terminal side of angle C is in quadrant two.
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Note: since sin^2 + cos^2 = 1,
dividing by cos^2 you get,
tan^2 + 1 = sec^2
So, sec^2 - tan^2 = 1
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Your Problem::
sec^2(C) - tan^2(C) = 1
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Cheers,
Stan H.</PRE>