Question 74209
If we let k=6 then we get
{{{6x+3y=3}}}
{{{12x+6y=6}}}
Notice how the 2nd equation is just two times the first equation (ie  {{{2(6x+3y)=2(3)}}} becomes {{{12x+6y=6}}}) Since one equation is a multiple of the other and the system is dependent, there are infinite solutions. In other words, the two equations produce the same line, but one equation is just twice the other.