Question 882682
{{{y=a(x-3)(x+2)}}}
Now put the equation into vertex form to find the maximum,
{{{y/a=x^2-x-6}}}
{{{y/a=(x^2-x+1/4)-6-1/4}}}
{{{y/a=(x-1/2)^2-25/4}}}
{{{y=a(x-1/2)^2-(25/4)a}}}
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{{{-(25/4)a=25/2}}}
{{{a=-2}}}
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{{{y=-2(x-3)(x+2)}}}