Question 882665
Collinear; the slope between any pair of the three points is the same, allowing....


{{{(0-1)/a-1)=(b-1)/(0-1)}}}  and  {{{(0-b)/(a-0)=(b-1)/(0-1)}}};
{{{1/(1-a)=1-b}}}   and   {{{-b/a=1-b}}};
{{{1=(1-a-b+ab)}}}   and    {{{-b=a-ab}}};
ab-a-b=0    and    a-ab+b=0
-a-b+ab=0   and   a+b-ab=0
a+b-ab=0


Simple sense about some common number facts may allow seeing that you may be able to see that if a=b=0, this will work, and if a=b=2, this will also work.  Any other ways you see?  Try testing any pick for a and find the corresponding value for b.  Will the combination also work?