Question 882546
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Let 
the second number = x
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The first number is 5 more than the second.
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The first number = x+5
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The third number is 4 times the first.
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The third number = 4(x+5)
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The sum of three numbers is 121.
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x + x+5 + 4(x+5) = 121

Solve and get x = 16

The first number = x+5 = 16+5 = 21
The second number = x = 16
The third number = 4(x+5) = 4(16+5) = 4(21) = 84

Edwin</pre>