Question 882117
<pre>
f(x) = 29x<sup>2</sup> + 3x + 4

Replace every x by (x+15)

f((x+15)) = 29(x+15)<sup>2</sup> + 3(x+15) + 4

f(x+15) = 29(x+15)(x+15) + 3x+45 + 4

f(x+15) = 29(x<sup>2</sup>+30x+225) + 3x+45 + 4

f(x+15) = 29x<sup>2</sup>+870x+6525 + 3x+45 + 4

f(x+15) = 29x</sup>2+873x+6574

g(x) = f(x+15) = 29x</sup>2+873x+6574

Edwin</pre>