Question 881966
The area of the larger circle is 36 Pi in2 Find the circumference of one of the smaller circles. There are two smaller circles inside the larger circle.
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assume diameter of smaller circles=1/2 that of the larger circle
πr^2=area 
πr^2=36π
r^2=36
r=6 (radius of larger circle)
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r/2=3=radius of smaller circle
circumference of smaller circle=2π*radius=2π*3=6π=18.85in