Question 881970
(3^x)(9^x-1) = 27^1-x 
(3^x)(3^2(x-1) = 3^3(1-x) 
(3^x)(3^(2x-2) = 3^(3-3x) 
3^(3x-2) = 3^(3-3x)
3x-2=3-3x
6x=5
x=5/6
Check:
3^(5/6)*9^(-1/6)=27^1/6
(3^(5/6))/9^(1/6)=3^(3/6)
(3^(5/6))/3^(2/6)=3^(3/6)
3^(3/6)=3^(3/6)
check ok