Question 881727
If a woman invested $10,000 at 8% annual interest, how much more must she invest at 9% so that her annual income will exceed $1,250?
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let x=amount invested at 9% so annual income will = $1,250

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9%x+8%(10000)=1250
.09x+800=1250
.09x=450
x=5000
how much more must she invest at 9% so that her annual income will exceed $1,250? >$5000